Another Peek Beyond the Point | FIO

Question 17

Evaluate the following using the information 156×12=1872156 \times 12 = 1872:

(a) 15.6×1.2=15.6 \times 1.2 = \underline{\quad\quad\quad\quad}

(b) 187.2÷1.2=187.2 \div 1.2 = \underline{\quad\quad\quad\quad}

(c) 18.72÷15.6=18.72 \div 15.6 = \underline{\quad\quad\quad\quad}

(d) 0.156×0.12=0.156 \times 0.12 = \underline{\quad\quad\quad\quad}

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Solution
Understand the Question
  • We are given the basic arithmetic relationship: 156×12=1872156 \times 12 = 1872
  • From this multiplication fact, the corresponding division facts are: 1872÷12=156and1872÷156=121872 \div 12 = 156 \quad \text{and} \quad 1872 \div 156 = 12
  • To evaluate decimals with these base digits, express decimals as fractions or division by powers of 1010 (10,100,1000,10, 100, 1000, \dots), apply the known fact, and adjust the decimal point accordingly.

(a) 15.6×1.2=15.6 \times 1.2 = \underline{\quad\quad\quad\quad}

Step 1 · Calculate 15.6×1.215.6 \times 1.2

Given 156×12=1872156 \times 12 = 1872.

Diagram 1

15.6×1.2=(156÷10)×(12÷10)=(156×12)÷(10×10)=1872÷100=18.72\begin{aligned} 15.6 \times 1.2 &= (156 \div 10) \times (12 \div 10) \\[0.6em] &= (156 \times 12) \div (10 \times 10) \\[0.6em] &= 1872 \div 100 \\[0.6em] &= 18.72 \end{aligned}
Answer

(a) 18.7218.72

(b) 187.2÷1.2=187.2 \div 1.2 = \underline{\quad\quad\quad\quad}

Step 1 · Calculate 187.2÷1.2187.2 \div 1.2

Given 156×12=1872    1872÷12=156156 \times 12 = 1872 \implies 1872 \div 12 = 156.

Diagram 2

187.2÷1.2=(1872÷10)÷(12÷10)=(1872÷10)×(10÷12)=1872÷12=156\begin{aligned} 187.2 \div 1.2 &= (1872 \div 10) \div (12 \div 10) \\[0.6em] &= (1872 \div 10) \times (10 \div 12) \\[0.6em] &= 1872 \div 12 \\[0.6em] &= 156 \end{aligned}
Answer

(b) 156156

(c) 18.72÷15.6=18.72 \div 15.6 = \underline{\quad\quad\quad\quad}

Step 1 · Calculate 18.72÷15.618.72 \div 15.6

Given 156×12=1872    1872÷156=12156 \times 12 = 1872 \implies 1872 \div 156 = 12.

18.72÷15.6=(1872÷100)÷(156÷10)=(1872÷100)×(10÷156)=(1872÷156)×(10÷100)=12×(1÷10)=12×0.1=1.2\begin{aligned} 18.72 \div 15.6 &= (1872 \div 100) \div (156 \div 10) \\[0.6em] &= (1872 \div 100) \times (10 \div 156) \\[0.6em] &= (1872 \div 156) \times (10 \div 100) \\[0.6em] &= 12 \times (1 \div 10) \\[0.6em] &= 12 \times 0.1 \\[0.6em] &= 1.2 \end{aligned}
Answer

(c) 1.21.2

(d) 0.156×0.12=0.156 \times 0.12 = \underline{\quad\quad\quad\quad}

Step 1 · Calculate 0.156×0.120.156 \times 0.12

Given 156×12=1872156 \times 12 = 1872.

Diagram 4

0.156×0.12=(156÷1000)×(12÷100)=(156×12)÷(1000×100)=1872÷100000=0.01872\begin{aligned} 0.156 \times 0.12 &= (156 \div 1000) \times (12 \div 100) \\[0.6em] &= (156 \times 12) \div (1000 \times 100) \\[0.6em] &= 1872 \div 100000 \\[0.6em] &= 0.01872 \end{aligned}
Answer

(d) 0.018720.01872

Common Mistakes
  • Missing Leading Zeros in Multiplication: In part (d), 0.156×0.120.156 \times 0.12 has 3+2=53 + 2 = 5 decimal places. Writing 0.18720.1872 instead of inserting a placeholder zero to get 0.018720.01872 is a frequent mistake.
  • Miscounting Decimal Places in Division: In division, the number of decimal places in the quotient is (places in dividend)(places in divisor)(\text{places in dividend}) - (\text{places in divisor}). For example, in (b), 11=01 - 1 = 0 decimal places, giving 156156 (an integer).

More questions in FIO

Q1

Recall that a tenth is 0.10.1, a hundredth is 0.010.01, and so on. Find the following products in tenths, hundredths and so on:

(a) 6×4 tenths=24 tenths6 \times 4 \text{ tenths} = 24 \text{ tenths}

(b) 7×0.37 \times 0.3

(c) 9×5 hundredths9 \times 5 \text{ hundredths}

Q2

Find the products:

(a) 27.34×627.34 \times 6

(b) 4.23×3.74.23 \times 3.7

(c) 0.432×0.230.432 \times 0.23

Q3

Thejus needs 1.65 m1.65 \text{ m} of cloth for a shirt. How many metres of cloth are needed for 33 shirts?

Q4

Meenu bought 4 notebooks and 3 erasers. The cost of each book was ₹15.50 and each eraser was ₹2.75. How much did she spend in all?

Q5

The thickness of a rupee coin is 1.45 mm1.45 \text{ mm}. What is the total height of the cylinder formed by placing 36 rupee coins one over the other? Write the answer in centimeters.

Q6

The price of 1 kg of oranges is ₹56.50. What is the price of 2.250 kg of oranges? Can we write 56.50 as 56.5 and 2.250 as 2.25 and multiply? Will we get the same product? Why?

Q7

Dwarakanath purchases notebooks at a wholesale price of ₹23.6 per piece and sells each notebook at ₹30/-. How much profit does he make if he sells 50 books in a week?

Q8

Given that 18×12=21618 \times 12 = 216, find the products:

(a) 18×1.218 \times 1.2 (b) 18×0.1218 \times 0.12 (c) 1.8×1.21.8 \times 1.2 (d) 0.18×0.120.18 \times 0.12 (e) 0.018×0.0120.018 \times 0.012 (f) 1.8×121.8 \times 12

In which of the cases above is the product less than 1?

Q9

In which of the following multiplications is the product less than 1? Can you find the answer without actually doing the multiplications?

(a) 7×0.67 \times 0.6

(b) 0.7×0.60.7 \times 0.6

(c) 0.7×60.7 \times 6

(d) 0.07×0.060.07 \times 0.06

Q10

Multiplying the following numbers by 1010, 100100 and 10001000 to complete the table.

Q11

Find the quotient by converting the denominator into 1, 10, 100 or 1000 and verify the solution by the long division method (division by place value).

(a) 185\dfrac{18}{5} (b) 4154\dfrac{415}{4} (c) 12172\dfrac{1217}{2} (d) 48278\dfrac{4827}{8}

Q12

Choose the correct answer:

(a) 15264=\dfrac{1526}{4} =

(i) 38.15

(ii) 380.15

(iii) 381.5

(iv) 381.05

(b) 35678=\dfrac{3567}{8} =

(i) 4458.75

(ii) 44.5875

(iii) 445.875

(iv) 4458.75

Q13

What is the quotient?

(a) 132÷4=132 \div 4 =

(b) 13.2÷4=13.2 \div 4 =

(c) 1.32÷4=1.32 \div 4 =

(d) 0.132÷4=0.132 \div 4 =

Q14

What is the quotient?

(a) 126÷8=126 \div 8 =

(b) 12.6÷8=12.6 \div 8 =

(c) 1.26÷8=1.26 \div 8 =

(d) 0.126÷8=0.126 \div 8 =

(e) 0.0126÷8=0.0126 \div 8 =

Q15

Express the following fractions in decimal form:

(a) 25\dfrac{2}{5}

(b) 134\dfrac{13}{4}

(c) 450\dfrac{4}{50}

(d) 58\dfrac{5}{8}

Q16

Find the quotients:

(a) 24.86÷1.224.86 \div 1.2

(b) 5.728÷1.525.728 \div 1.52

Q17

Evaluate the following using the information 156×12=1872156 \times 12 = 1872:

(a) 15.6×1.2=15.6 \times 1.2 = \underline{\quad\quad\quad\quad}

(b) 187.2÷1.2=187.2 \div 1.2 = \underline{\quad\quad\quad\quad}

(c) 18.72÷15.6=18.72 \div 15.6 = \underline{\quad\quad\quad\quad}

(d) 0.156×0.12=0.156 \times 0.12 = \underline{\quad\quad\quad\quad}

Q18

Evaluate the following:

(a) 25÷=0.02525 \div \underline{\quad\quad} = 0.025

(b) 25÷=25025 \div \underline{\quad\quad} = 250

(c) 25÷=2.525 \div \underline{\quad\quad} = 2.5

(d) 25÷10=25×25 \div 10 = 25 \times \underline{\quad\quad}

(e) 25÷0.10=25×25 \div 0.10 = 25 \times \underline{\quad\quad}

(f) 25÷0.01=25×25 \div 0.01 = 25 \times \underline{\quad\quad}

Q19

Find the quotient:

(a) 2.46÷1.5=2.46 \div 1.5 =

(b) 2.46÷0.15=2.46 \div 0.15 =

(c) 2.46÷0.015=2.46 \div 0.015 =

Is the quotient obtained in 24.6÷1.524.6 \div 1.5 the same as the quotient obtained in 2.46÷0.152.46 \div 0.15?

Q20

A 4 m4\text{ m} long wooden block has to be cut into 55 pieces of equal length. What is the length of each piece?

Q21

If the perimeter of a regular polygon with 12 sides is 208.8 cm, what is the length of its side?

Q22

3 litres of watermelon juice is shared among 8 friends equally. How much watermelon juice will each get? Express the quantity of juice in millilitres.

Q23

A car covers 234.45 km using 12.6 litres of petrol. What is the distance travelled per litre?

Q24

5 kg of flour (aata) was distributed equally among 15 students. How much flour did each student receive?

Q25

A 210 gram packet of peanut chikki costs ₹70.5, while a 110 gram packet of potato chips costs ₹33.25. Which is cheaper?

Q26

Write the decimal number at the arrow mark:

Q27

Shyamala bought 3 kg bananas at ₹30/- per kg. She counted 35 bananas in all. She sells each banana for ₹5/-. How much profit does she make selling all the bananas?

Q28

A teacher placed textbooks that are 2.5 cm thick on a bookshelf. The teacher wanted to place 80 textbooks on the shelf. The bookshelf is 160 cm long. How many books could be placed on the shelf? Was there any space left? If yes, how much?

Q29

Fill in the following blanks appropriately:

(a) 5.5 km= m5.5\text{ km} = \underline{\hspace{1.5cm}}\text{ m}

(b) 35 cm= m35\text{ cm} = \underline{\hspace{1.5cm}}\text{ m}

(c) 14.5 cm= mm14.5\text{ cm} = \underline{\hspace{1.5cm}}\text{ mm}

(d) 68 g= kg68\text{ g} = \underline{\hspace{1.5cm}}\text{ kg}

(e) 9.02 m= mm9.02\text{ m} = \underline{\hspace{1.5cm}}\text{ mm}

(f) 125.5 ml= l125.5\text{ ml} = \underline{\hspace{1.5cm}}\text{ l}

Q30

The following problem was set by Sridharacharya in his book, Patiganita. “6146\dfrac{1}{4} is divided by 2122\dfrac{1}{2}, and 601460\dfrac{1}{4} is divided by 3123\dfrac{1}{2}. Tell the quotients separately.” Can you try to solve it by converting the fractions into decimals?

Q31

Fill the boxes in at least 2 different ways:

(a) ×=2.4\square \times \square = 2.4

(b) ×=14.5\square \times \square = 14.5

Q32

Find the following quotients given that 756÷36=21756 \div 36 = 21:

(a) 75.6÷3.675.6 \div 3.6

(b) 7.56÷0.367.56 \div 0.36

(c) 756÷0.36756 \div 0.36

(d) 75.6÷36075.6 \div 360

(e) 7560÷3.67560 \div 3.6

(f) 7.56÷0.367.56 \div 0.36

Q33

Find the missing cells if each cell represents a÷ba \div b:

Q34

Using the digits 2, 4, 5, 8, and 0 fill the boxes to get the:

(a) maximum product

(b) minimum product

(c) product greater than 150

(d) product nearest to 100

(e) product nearest to 5

Q35

Sort the following expressions in increasing order:

(a) 245.05×0.942368245.05 \times 0.942368

(b) 245.05×7.9682245.05 \times 7.9682

(c) 245.05÷7.9682245.05 \div 7.9682

(d) 245.05÷0.942368245.05 \div 0.942368

(e) 245.05245.05

(f) 7.96827.9682

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