Another Peek Beyond the Point | FIO

Question 23

A car covers 234.45 km using 12.6 litres of petrol. What is the distance travelled per litre?

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Solution

We need to find the distance covered for each litre of petrol.

Step 1 — Understand the problem

The car covers a certain distance. It uses some petrol for this. We are given the total distance. We are given the total petrol used. We need to find distance per litre. This means we divide total distance by total petrol.

Distance per litre=Total distanceTotal petrol\text{Distance per litre} = \frac{\text{Total distance}}{\text{Total petrol}}

Step 2 — Write down the given values

The total distance covered is 234.45 km. The total petrol used is 12.6 litres.

Step 3 — Prepare for division

We need to divide 234.45 by 12.6. It is easier to divide whole numbers. Let us remove the decimal points. We multiply both numbers by 100. This makes the divisor a whole number. It also makes the dividend a whole number.

234.4512.6=234.45×10012.6×100\frac{234.45}{12.6} = \frac{234.45 \times 100}{12.6 \times 100}

=234451260= \frac{23445}{1260}

Step 4 — Perform the division

Now we divide 23445 by 1260. Let us do long division.

23445÷126023445 \div 1260

=18.60714...= 18.60714...

We can round this to three decimal places. The fourth decimal place is 1. So, we keep the third decimal place as 7.

18.607 km/litre\boxed{18.607 \text{ km/litre}}

Diagram 1

Answer

(i) The distance travelled per litre is 18.607 km.

More questions in FIO

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Recall that a tenth is 0.1, a hundredth is 0.01, and so on. Find the following products in tenths, hundredths and so on:

(a) 6 × 4 tenths = 24 tenths (b) 7 × 0.3 (c) 9 × 5 hundredths

Q2

Find the products:

(a) 27.34×627.34 \times 6

(b) 4.23×3.74.23 \times 3.7

(c) 0.432×0.230.432 \times 0.23

Q3

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Q4

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Q5

The thickness of a rupee coin is 1.45 mm. What is the total height of the cylinder formed by placing 36 rupee coins one over the other? Write the answer in centimeters.

Q6

The price of 1 kg of oranges is ₹56.50. What is the price of 2.250 kg of oranges? Can we write 56.50 as 56.5 and 2.250 as 2.25 and multiply? Will we get the same product? Why?

Q7

Dwarakanath purchases notebooks at a wholesale price of ₹23.6 per piece and sells each notebook at ₹30/-. How much profit does he make if he sells 50 books in a week?

Q8

Given that 18 × 12 = 216, find the products:

(a) 18 × 1.2 (b) 18 × 0.12 (c) 1.8 × 1.2 (d) 0.18 × 0.12 (e) 0.018 × 0.012 (f) 1.8 × 12

In which of the cases above is the product less than 1?

Q9

In which of the following multiplications is the product less than 1? Can you find the answer without actually doing the multiplications?

(a) 7×0.67 \times 0.6

(b) 0.7×0.60.7 \times 0.6

(c) 0.7×60.7 \times 6

(d) 0.07×0.060.07 \times 0.06

Q10

Multiplying the following numbers by 10, 100 and 1000 to complete the table.

Q11

Find the quotient by converting the denominator into 1, 10, 100 or 1000 and verify the solution by the long division method (division by place value).

(a) 185\frac{18}{5} (b) 4154\frac{415}{4} (c) 12172\frac{1217}{2} (d) 48278\frac{4827}{8}

Q12

Choose the correct answer:

(a) 15264=\frac{1526}{4} =

(i) 38.15

(ii) 380.15

(iii) 381.5

(iv) 381.05

(b) 35678=\frac{3567}{8} =

(i) 4458.75

(ii) 44.5875

(iii) 445.875

(iv) 4458.75

Q13

What is the quotient?

(a) 132÷4=132 \div 4 =

(b) 13.2÷4=13.2 \div 4 =

(c) 1.32÷4=1.32 \div 4 =

(d) 0.132÷4=0.132 \div 4 =

Q14

What is the quotient?

(a) 126÷8=126 \div 8 =

(b) 12.6÷8=12.6 \div 8 =

(c) 1.26÷8=1.26 \div 8 =

(d) 0.126÷8=0.126 \div 8 =

(e) 0.0126÷8=0.0126 \div 8 =

Q15

Express the following fractions in decimal form:

(a) 25\frac{2}{5}

(b) 134\frac{13}{4}

(c) 450\frac{4}{50}

(d) 58\frac{5}{8}

Q16

Find the quotients:

(a) 24.86÷1.224.86 \div 1.2

(b) 5.728÷1.525.728 \div 1.52

Q17

Evaluate the following using the information 156×12=1872156 \times 12 = 1872:

(a) 15.6×1.2=15.6 \times 1.2 = \underline{\quad\quad\quad\quad}

(b) 187.2÷1.2=187.2 \div 1.2 = \underline{\quad\quad\quad\quad}

(c) 18.72÷15.6=18.72 \div 15.6 = \underline{\quad\quad\quad\quad}

(d) 0.156×0.12=0.156 \times 0.12 = \underline{\quad\quad\quad\quad}

Q18

Evaluate the following:

(a) 25÷=0.02525 \div \underline{\quad\quad} = 0.025

(b) 25÷=25025 \div \underline{\quad\quad} = 250

(c) 25÷=2.525 \div \underline{\quad\quad} = 2.5

(d) 25÷10=25×25 \div 10 = 25 \times \underline{\quad\quad}

(e) 25÷0.10=25×25 \div 0.10 = 25 \times \underline{\quad\quad}

(f) 25÷0.01=25×25 \div 0.01 = 25 \times \underline{\quad\quad}

Q19

Find the quotient:

(a) 2.46÷1.5=2.46 \div 1.5 =

(b) 2.46÷0.15=2.46 \div 0.15 =

(c) 2.46÷0.015=2.46 \div 0.015 =

Is the quotient obtained in 24.6÷1.524.6 \div 1.5 the same as the quotient obtained in 2.46÷0.152.46 \div 0.15?

Q20

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Q22

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Q23

A car covers 234.45 km using 12.6 litres of petrol. What is the distance travelled per litre?

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Q26

Write the decimal number at the arrow mark:

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Q28

A teacher placed textbooks that are 2.5 cm thick on a bookshelf. The teacher wanted to place 80 textbooks on the shelf. The bookshelf is 160 cm long. How many books could be placed on the shelf? Was there any space left? If yes, how much?

Q29

Fill in the following blanks appropriately:

(a) 5.5 km= m5.5\text{ km} = \underline{\hspace{1.5cm}}\text{ m}

(b) 35 cm= m35\text{ cm} = \underline{\hspace{1.5cm}}\text{ m}

(c) 14.5 cm= mm14.5\text{ cm} = \underline{\hspace{1.5cm}}\text{ mm}

(d) 68 g= kg68\text{ g} = \underline{\hspace{1.5cm}}\text{ kg}

(e) 9.02 m= mm9.02\text{ m} = \underline{\hspace{1.5cm}}\text{ mm}

(f) 125.5 ml= l125.5\text{ ml} = \underline{\hspace{1.5cm}}\text{ l}

Q30

The following problem was set by Sridharacharya in his book, Patiganita. “6146 \frac{1}{4} is divided by 2122 \frac{1}{2}, and 601460 \frac{1}{4} is divided by 3123 \frac{1}{2}. Tell the quotients separately.” Can you try to solve it by converting the fractions into decimals?

Q31

Fill the boxes in at least 2 different ways:

(a) ×=2.4\square \times \square = 2.4

(b) ×=14.5\square \times \square = 14.5

Q32

Find the following quotients given that 756÷36=21756 \div 36 = 21:

(a) 75.6÷3.675.6 \div 3.6

(b) 7.56÷0.367.56 \div 0.36

(c) 756÷0.36756 \div 0.36

(d) 75.6÷36075.6 \div 360

(e) 7560÷3.67560 \div 3.6

(f) 7.56÷0.367.56 \div 0.36

Q33

Find the missing cells if each cell represents a÷b:

Q34

Using the digits 2, 4, 5, 8, and 0 fill the boxes to get the:

(a) maximum product

(b) minimum product

(c) product greater than 150

(d) product nearest to 100

(e) product nearest to 5

Q35

Sort the following expressions in increasing order:

(a) 245.05×0.942368245.05 \times 0.942368

(b) 245.05×7.9682245.05 \times 7.9682

(c) 245.05÷7.9682245.05 \div 7.9682

(d) 245.05÷0.942368245.05 \div 0.942368

(e) 245.05245.05

(f) 7.96827.9682

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