Real Numbers | Exercise 1.1

Question 1

Express each number as a product of its prime factors:

(i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

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Solution
Understand the Question
  • To express a number as a product of its prime factors, divide the number successively by the smallest possible prime numbers (2,3,5,7,11,13,17,2, 3, 5, 7, 11, 13, 17, \dots) until the quotient becomes 11.
  • Write repeated prime factors in exponential form (e.g., 2×2=222 \times 2 = 2^2).

(i) 140

Step 1 · Prime Factorise 140

Diagram 1

140÷2=7070÷2=3535÷5=77÷7=1\begin{aligned} 140 \div 2 &= 70 \\ 70 \div 2 &= 35 \\ 35 \div 5 &= 7 \\ 7 \div 7 &= 1 \end{aligned} 140=2×2×5×7=22×5×7140 = 2 \times 2 \times 5 \times 7 = 2^2 \times 5 \times 7
Answer

(i) 22×5×72^2 \times 5 \times 7

(ii) 156

Step 1 · Prime Factorise 156

Diagram 2

156÷2=7878÷2=3939÷3=1313÷13=1\begin{aligned} 156 \div 2 &= 78 \\ 78 \div 2 &= 39 \\ 39 \div 3 &= 13 \\ 13 \div 13 &= 1 \end{aligned} 156=2×2×3×13=22×3×13156 = 2 \times 2 \times 3 \times 13 = 2^2 \times 3 \times 13
Answer

(ii) 22×3×132^2 \times 3 \times 13

(iii) 3825

Step 1 · Prime Factorise 3825

3825÷3=12751275÷3=425425÷5=8585÷5=1717÷17=1\begin{aligned} 3825 \div 3 &= 1275 \\ 1275 \div 3 &= 425 \\ 425 \div 5 &= 85 \\ 85 \div 5 &= 17 \\ 17 \div 17 &= 1 \end{aligned} 3825=3×3×5×5×17=32×52×173825 = 3 \times 3 \times 5 \times 5 \times 17 = 3^2 \times 5^2 \times 17
Answer

(iii) 32×52×173^2 \times 5^2 \times 17

(iv) 5005

Step 1 · Prime Factorise 5005

5005÷5=10011001÷7=143143÷11=1313÷13=1\begin{aligned} 5005 \div 5 &= 1001 \\ 1001 \div 7 &= 143 \\ 143 \div 11 &= 13 \\ 13 \div 13 &= 1 \end{aligned} 5005=5×7×11×135005 = 5 \times 7 \times 11 \times 13
Answer

(iv) 5×7×11×135 \times 7 \times 11 \times 13

(v) 7429

Step 1 · Prime Factorise 7429

7429÷17=437437÷19=2323÷23=1\begin{aligned} 7429 \div 17 &= 437 \\ 437 \div 19 &= 23 \\ 23 \div 23 &= 1 \end{aligned} 7429=17×19×237429 = 17 \times 19 \times 23
Answer

(v) 17×19×2317 \times 19 \times 23

Common Mistakes
  • Dividing by Composite Numbers: Dividing by composite numbers like 4,6,94, 6, 9 instead of prime numbers.
  • Testing Larger Primes: For numbers like 74297429, which have no small prime factors (2,3,5,7,11,132, 3, 5, 7, 11, 13), test systematically with larger prime numbers like 17,19,2317, 19, 23.
  • Exponential Notation: Forgetting to write repeated factors in exponential form (e.g., writing 2×22 \times 2 instead of 222^2).

More questions in Exercise 1.1

Q1

Express each number as a product of its prime factors:

(i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Q2

Find the LCM and HCF of the following pairs of integers and verify that LCM×HCF=product of the two numbers\text{LCM} \times \text{HCF} = \text{product of the two numbers}.

(i) 26 and 91

(ii) 510 and 92

(iii) 336 and 54

Q3

Find the LCM and HCF of the following integers by applying the prime factorisation method.

(i) 12, 15 and 21

(ii) 17, 23 and 29

(iii) 8, 9 and 25

Q4

Given that HCF(306,657)=9\text{HCF}(306, 657) = 9, find LCM(306,657)\text{LCM}(306, 657).

Q5

Check whether 6n6^n can end with the digit 0 for any natural number nn.

Q6

Explain why 7×11×13+137 \times 11 \times 13 + 13 and 7×6×5×4×3×2×1+57 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 + 5 are composite numbers.

Q7

There is a circular path around a sports field. Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same. Suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point?

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