Real Numbers | Exercise 1.1

Question 6

Explain why 7×11×13+137 \times 11 \times 13 + 13 and 7×6×5×4×3×2×1+57 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 + 5 are composite numbers.

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Solution

Composite numbers have factors other than 1 and the number itself.

Step 1 — First expression analysis

Let's look at the first expression. We see that 13 is a common factor. We can take 13 out.

7×11×13+137 \times 11 \times 13 + 13

=13×(7×11+1)= 13 \times (7 \times 11 + 1)

=13×(77+1)= 13 \times (77 + 1)

=13×78= 13 \times 78

We can break down 78 further.

=13×(13×6)= 13 \times (13 \times 6)

=13×13×6\boxed{= 13 \times 13 \times 6}

The number has factors like 6 and 13. These are not 1 or the number itself. So, it is a composite number.

Step 2 — Second expression analysis

Now let's check the second expression. We see that 5 is a common factor. We can take 5 out.

7×6×5×4×3×2×1+57 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 + 5

=5×(7×6×4×3×2×1+1)= 5 \times (7 \times 6 \times 4 \times 3 \times 2 \times 1 + 1)

Let's calculate the product inside.

7×6×4×3×2×1=10087 \times 6 \times 4 \times 3 \times 2 \times 1 = 1008

Now we substitute this value.

=5×(1008+1)= 5 \times (1008 + 1)

=5×1009\boxed{= 5 \times 1009}

The number 1009 is a prime number. The number has factors like 5 and 1009. These are not 1 or the number itself. So, it is a composite number.

Answer

(i) 7×11×13+137 \times 11 \times 13 + 13 is a composite number. (ii) 7×6×5×4×3×2×1+57 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 + 5 is a composite number.

More questions in Exercise 1.1

Q1

Express each number as a product of its prime factors:

(i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Q2

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers.

(i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54

Q3

Find the LCM and HCF of the following integers by applying the prime factorisation method.

(i) 12, 15 and 21 (ii) 17, 23 and 29 (iii) 8, 9 and 25

Q4

Given that HCF (306, 657) = 9, find LCM (306, 657).

Q5

Check whether 6n6^n can end with the digit 0 for any natural number nn.

Q6

Explain why 7×11×13+137 \times 11 \times 13 + 13 and 7×6×5×4×3×2×1+57 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 + 5 are composite numbers.

Q7

There is a circular path around a sports field. Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same. Suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point?

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