A Tale of Three Intersecting Lines | IT

Question 6

  1. How do we construct triangles that are not equilateral?

  2. Construct a triangle of sidelength 4 cm4\text{ cm}, 5 cm5\text{ cm} and 6 cm6\text{ cm}.

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Solution
Understand the Question
  • A triangle that is not equilateral has either two equal sides (isosceles) or all three sides of different lengths (scalene).
  • For any valid triangle with side lengths aa, bb, and cc, the Triangle Inequality Theorem must be satisfied: the sum of the lengths of any two sides must be strictly greater than the third side (a+b>ca+b > c, b+c>ab+c > a, and a+c>ba+c > b).
  • To construct a triangle using its three side lengths (SSS Criterion), draw the base line segment first, and use a compass to draw arcs from each endpoint whose intersection gives the third vertex.

(i) How do we construct triangles that are not equilateral?

Step 1 · State the Conditions for a Non-Equilateral Triangle

To construct a non-equilateral triangle, choose three side lengths aa, bb, and cc such that they are not all equal, and they satisfy the triangle inequality property:

a+b>ca+c>bb+c>a\begin{aligned} a + b &> c \\ a + c &> b \\ b + c &> a \end{aligned}

Step 2 · Verify Triangle Inequality with an Example

For side lengths 4 cm4\text{ cm}, 5 cm5\text{ cm}, and 6 cm6\text{ cm}:

4+5>6    9>6(True)4+6>5    10>5(True)5+6>4    11>4(True)\begin{aligned} 4 + 5 > 6 &\implies 9 > 6 \quad \text{(True)} \\ 4 + 6 > 5 &\implies 10 > 5 \quad \text{(True)} \\ 5 + 6 > 4 &\implies 11 > 4 \quad \text{(True)} \end{aligned}

Since all three conditions hold true and the sides are of different lengths, these lengths form a valid scalene (non-equilateral) triangle.

Answer

(i) Choose three side lengths that are not all equal and satisfy the triangle inequality theorem (a+b>ca+b > c, a+c>ba+c > b, and b+c>ab+c > a).

(ii) Construct a triangle of sidelength 4 cm4\text{ cm}, 5 cm5\text{ cm} and 6 cm6\text{ cm}.

Step 1 · Draw the Base

Draw a line segment AB=6 cmAB = 6\text{ cm}.Diagram 1

Step 2 · Draw the First Arc

With point AA as the centre and a compass radius of 4 cm4\text{ cm}, draw an arc above ABAB.Diagram 2

Step 3 · Draw the Second Arc to Find Point C

With point BB as the centre and a compass radius of 5 cm5\text{ cm}, draw another arc intersecting the previous arc at point CC.Diagram 3

Step 4 · Complete the Triangle

Join AA to CC and BB to CC to obtain ΔABC\Delta ABC with sides 4 cm4\text{ cm}, 5 cm5\text{ cm}, and 6 cm6\text{ cm}.

Answer

(ii) ΔABC\Delta ABC is constructed with sides AB=6 cmAB = 6\text{ cm}, AC=4 cmAC = 4\text{ cm}, and BC=5 cmBC = 5\text{ cm}.

Common Mistakes
  • Violating Triangle Inequality: Choosing side lengths where the sum of the two shorter sides is not greater than the longest side (e.g., 2 cm2\text{ cm}, 3 cm3\text{ cm}, 6 cm6\text{ cm} cannot form a triangle because 2+3<62 + 3 < 6).
  • Swapping Compass Radii: Using the 5 cm5\text{ cm} radius at vertex AA and 4 cm4\text{ cm} at vertex BB, which inverts the orientation of the side lengths.

More questions in IT

Q1

What happens when the three vertices lie on a straight line?

Q2

Construct a triangle in which all the sides are of length 4 cm.

Q3

Context: Construct a triangle in which all the sides are of length 4 cm.

Q. How did you construct this triangle and what tools did you use? Can this construction be done only using a marked ruler (and a pencil)?

Q4

Q. How do we make this construction more efficient?

Q5

Context: Step 2: Construct another arc of radius 4 cm4\text{ cm} from BB. Let CC be the point of intersection of the arcs.

Q. The construction ensures that both ACAC and BCBC are of length 4 cm4\text{ cm}. Can you see why?

Q6
  1. How do we construct triangles that are not equilateral?

  2. Construct a triangle of sidelength 4 cm4\text{ cm}, 5 cm5\text{ cm} and 6 cm6\text{ cm}.

Q7

Context: Construct a triangle of sidelength 4 cm4\text{ cm}, 5 cm5\text{ cm} and 6 cm6\text{ cm}.

Q. How do we construct this triangle more efficiently?

Q8

Construct

Construct triangles having the following sidelengths (all the units are in cm):

(a) 44, 44, 66

(b) 33, 44, 55

(c) 11, 55, 55

(d) 44, 66, 88

(e) 3.53.5, 3.53.5, 3.53.5

Q9

Construct a triangle with sidelengths 3 cm3\text{ cm}, 4 cm4\text{ cm}, and 8 cm8\text{ cm}.

What is happening? Are you able to construct the triangle?

Q10

Here is another set of lengths: 2 cm2\text{ cm}, 3 cm3\text{ cm}, and 6 cm6\text{ cm}. Check if a triangle is possible for these sidelengths.

Q11

Try to find more sets of lengths for which a triangle construction is impossible. See if you can find any pattern in them.

Q12

Context: Clearly, the direct straight-line path from the tent to the tree is shorter than the roundabout path via the pole. In fact, the direct straight-line path is the shortest possible path to the tree from the tent. Will the direct path between any two points be shorter than the roundabout path via a third point? Clearly, the answer is yes.

Q. Can this understanding be used to tell something about the existence of a triangle having sidelengths 10 cm10\text{ cm}, 15 cm15\text{ cm} and 30 cm30\text{ cm}?

Q13

Can we say anything about the existence of a triangle having sidelengths 3 cm3\text{ cm}, 3 cm3\text{ cm} and 7 cm7\text{ cm}? Verify your answer by construction.

Q14

In the rough diagram in Fig. 7.4, is it possible to assign lengths in a different order such such that the direct paths are always coming out to be shorter than the roundabout paths? If this is possible, then a triangle might exist.

Q15

Context: "In the rough diagram in Fig. 7.4, is it possible to assign lengths in a different order such that the direct paths are always coming out to be shorter than the roundabout paths? If this is possible, then a triangle might exist."

Q. Is such rearrangement of lengths possible in the triangle?

Q16

Will this always happen? That is, for any set of lengths, will there be at least two comparisons where the direct length is less than the sum of the other two? Explore for different sets of lengths.

Q17

Further, for a given set of lengths, is it possible to identify which lengths will immediately be less than the sum of the other two, without calculations?

[Hint: Consider the direct lengths in the increasing order.]

Q18

Given three sidelengths, what do we need to compare to check for the existence of a triangle?

Q19

Context: Does a triangle exist with sidelengths 4 cm4\text{ cm}, 5 cm5\text{ cm} and 8 cm8\text{ cm}? This satisfies the triangle inequality:

8<4+5=98 < 4 + 5 = 9

Q. Why do we not need to check the other two sides?

Q20

Now, suppose that a circle of radius 5 cm5 \text{ cm} is constructed, centred at BB. Can you draw a rough diagram of the resulting figure?

Q21

Will triangles always exist when a set of lengths satisfies the triangle inequality? How can we be sure?

Q22

Q. Let us study each of these cases by finding the relation between the radii (the smaller two lengths) and ABAB (longest length).

Q23

Context: Case 2: Circles do not intersect internally

Q. For this case to happen, what should be the relation between the radii and ABAB?

Q24

Can we use this analysis to tell if a triangle exists when the lengths satisfy the triangle inequality?

Q25

How will the two circles turn out for a set of lengths that do not satisfy the triangle inequality? Find 3 examples of sets of lengths for which the circles:

(a) touch each other at a point,

(b) do not intersect.

Q26

Frame a complete procedure that can be used to check the existence of a triangle.

Q27

We have seen that triangles do not exist for all sets of sidelengths. Is there a combination of measurements in the case of two sides and the included angle where a triangle is not possible? Justify your answer using what you observe during construction.

Q28

Do triangles exist for every combination of two angles and their included side? Explore.

Q29

Find examples of measurements of two angles with the included side where a triangle is not possible.

Q30

It is clear that if the line from BB is "inclined" sufficiently to the right, then it will not meet the line ll.

(a) Try to find a possible B\angle B (marked in the figure) for this to happen.

(b) What could be smallest value of B\angle B for the lines to not meet?

Q31

Like the triangle inequality, can you form a rule that describes the two angles for which a triangle is possible?

Can the sum of the two angles be used for framing this rule?

Q32

Context: Let us take two angles, say 6060^\circ and 7070^\circ, whose sum is less than 180180^\circ. Let the included side be 5 cm5\text{ cm}.

Q. What could the measure of the third angle be? Does this measure change if the base length is changed to some other value, say 7 cm7\text{ cm}? Construct and find out.

Q33

In general, once the two angles are fixed, does the third angle depend on the included sidelength? Try with different pairs of angles and lengths.

Q34

Try experimenting with different triangles to see if there is a relation between any two angles and the third one. To find this relation, what data will you keep track of and how will you organise the data you collect?

Q35

Context: Consider a triangle ABC with B=50\angle B = 50^\circ and C=70\angle C = 70^\circ. Suppose we construct a line XY parallel to BC through vertex A.

Q. We can see new angles being formed here: XAB\angle XAB and YAC\angle YAC. What are their values?

Q36

Angle Sum Property

What can we say about the sum of the angles of any triangle?

Q37

There is a convenient way of verifying the angle sum property by folding a triangular cut-out of a paper. Do you see how this shows that the sum of the angles in this triangle is 180180^\circ?

Q38

Find the exterior angle for different measures of A\angle A and B\angle B. Do you see any relation between the exterior angle and these two angles?

[Hint: From angle sum property, we have A+B+ACB=180\angle A + \angle B + \angle ACB = 180^\circ.]

We also have ACD+ACB=180\angle ACD + \angle ACB = 180^\circ, since they form a straight angle.

What does this show?

Q39

What would the altitude from AA to BC\text{BC} be in this triangle?

Q40

Construct an arbitrary triangle. Label the vertices A,B,CA, B, C taking BCBC to be the base.

Construct the altitude from AA to BCBC,

Q41

Context: Construction of the Altitudes of a Triangle Construct an arbitrary triangle. Label the vertices AA, BB, CC taking BC\text{BC} to be the base. Construct the altitude from AA to BC\text{BC}.

Q. Constructing the altitude using just a ruler is not accurate. To get a more precise angle of 9090^\circ, we use a set square along with a ruler.

Can you see how to do this?

Q42

Does there exist a triangle in which a side is also an altitude?

Visualise such a triangle and draw a rough diagram.

Q43

Context: In our study of triangles, we have encountered the following types of triangles; equilateral, isosceles, scalene and right-angled triangles.

Q. Did you spot any other type of triangle?

Q44

What are the other types of triangles based on angle measures?

Q45

What could an acute-angled triangle be? Can we define it as a triangle with one acute angle? Why not?

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