Question 4
The lengths of 40 leaves of a plant are measured correct to the nearest millimetre, and the data obtained is represented in the following table :
Find the median length of the leaves.
(Hint : The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 - 126.5, 126.5 - 135.5, . . . , 171.5 - 180.5.)

We need to find the median length of the leaves.
Step 1 — Convert to Continuous Classes
The given classes are not continuous. We need to make them continuous. We subtract 0.5 from lower limits. We add 0.5 to upper limits. The new classes are now continuous.
| Length (in mm) (Continuous Classes) | Number of leaves (f) | | :---------------------------------- | :------------------- | | 117.5 - 126.5 | 3 | | 126.5 - 135.5 | 5 | | 135.5 - 144.5 | 9 | | 144.5 - 153.5 | 12 | | 153.5 - 162.5 | 5 | | 162.5 - 171.5 | 4 | | 171.5 - 180.5 | 2 |

Step 2 — Calculate Cumulative Frequencies
Let's add a cumulative frequency column. This helps us find the median class. The total number of leaves, , is 40.
| Length (in mm) (Continuous Classes) | Number of leaves (f) | Cumulative Frequency (cf) | | :---------------------------------- | :------------------- | :------------------------ | | 117.5 - 126.5 | 3 | 3 | | 126.5 - 135.5 | 5 | 8 | | 135.5 - 144.5 | 9 | 17 | | 144.5 - 153.5 | 12 | 29 | | 153.5 - 162.5 | 5 | 34 | | 162.5 - 171.5 | 4 | 38 | | 171.5 - 180.5 | 2 | 40 |

Step 3 — Find Median Class
We find the value of . We look for the cumulative frequency just greater than 20. This is 29. The class corresponding to 29 is the median class. The median class is 144.5 - 153.5.
Step 4 — Apply Median Formula
The median formula is: Here, is the lower limit of the median class. . . is the cumulative frequency of the class before the median class. . is the frequency of the median class. . is the class size. Now, we substitute these values into the formula.
Answer
The median length of the leaves is 146.75 mm.
More questions in Exercise 13.3
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
If the median of the distribution given below is 28.5, find the values of and .
A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 year.
The lengths of 40 leaves of a plant are measured correct to the nearest millimetre, and the data obtained is represented in the following table :
Find the median length of the leaves.
(Hint : The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 - 126.5, 126.5 - 135.5, . . . , 171.5 - 180.5.)
The following table gives the distribution of the life time of 400 neon lamps :
Find the median life time of a lamp.
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.
The distribution below gives the weights of 30 students of a class. Find the median weight of the students.