Orienting Yourself: The Use of Coordinates | Exercise 1.1

Question 1

Fig. 1.3 shows Reiaan’s room with points OABC marking its corners. The x- and y-axes are marked in the figure. Point O is the origin.

Referring to Fig. 1.3, answer the following questions:

(i) If D1R1\text{D}_1\text{R}_1 represents the door to Reiaan’s room, how far is the door from the left wall (the y-axis) of the room? How far is the door from the x-axis?

(ii) What are the coordinates of D1\text{D}_1?

(iii) If R1\text{R}_1 is the point (11.5,0)(11.5, 0), how wide is the door? Do you think this is a comfortable width for the room door? If a person in a wheelchair wants to enter the room, will he/she be able to do so easily?

(iv) If B1 (0,1.5)\text{B}_1\ (0, 1.5) and B2 (0,4)\text{B}_2\ (0, 4) represent the ends of the bathroom door, is the bathroom door narrower or wider than the room door?

Question diagram 1
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Solution

We will use the given coordinates to find distances and compare door widths.

Step 1 — Door's position relative to walls

Let's find the door's distance from the left wall (y-axis). The door D1R1\text{D}_1\text{R}_1 starts at D1\text{D}_1. The x-coordinate of D1\text{D}_1 is 8. This is the distance from the y-axis.

Distance from y-axis=xD1\text{Distance from y-axis} = x_{\text{D}_1}

=8= 8

8 units\boxed{8 \text{ units}}

Let's find the door's distance from the x-axis. The door D1R1\text{D}_1\text{R}_1 lies on the x-axis. Its y-coordinate is 0.

Distance from x-axis=yD1\text{Distance from x-axis} = y_{\text{D}_1}

=0= 0

0 units\boxed{0 \text{ units}}

Diagram 1

Step 2 — Coordinates of D1

Let's identify the coordinates of point D1\text{D}_1. From the figure, D1\text{D}_1 is on the x-axis. Its x-coordinate is 8. Its y-coordinate is 0.

Coordinates of D1=(xD1,yD1)\text{Coordinates of D}_1 = (x_{\text{D}_1}, y_{\text{D}_1})

=(8,0)= (8, 0)

(8,0)\boxed{(8, 0)}

Diagram 2

Step 3 — Room door width and accessibility

Let's calculate the width of the room door. The door is between D1(8,0)\text{D}_1 (8, 0) and R1(11.5,0)\text{R}_1 (11.5, 0). The width is the difference in x-coordinates.

Width of room door=xR1xD1\text{Width of room door} = x_{\text{R}_1} - x_{\text{D}_1}

=11.58= 11.5 - 8

3.5 units\boxed{3.5 \text{ units}}

Now, let's consider if this width is comfortable. If 1 unit is 1 foot, then 3.5 units is 3.5 feet. This is equal to 42 inches. Standard room doors are typically 30-36 inches wide. So, 42 inches is a comfortable width.

Let's check for wheelchair accessibility. A wheelchair needs at least 32 inches clear width. Since 42 inches is greater than 32 inches, a wheelchair can pass easily. Yes, a person in a wheelchair will be able to enter easily.

Diagram 3

Step 4 — Bathroom door width comparison

Let's calculate the width of the bathroom door. The door is between B1(0,1.5)\text{B}_1 (0, 1.5) and B2(0,4)\text{B}_2 (0, 4). The width is the difference in y-coordinates.

Width of bathroom door=yB2yB1\text{Width of bathroom door} = y_{\text{B}_2} - y_{\text{B}_1}

=41.5= 4 - 1.5

2.5 units\boxed{2.5 \text{ units}}

Now, let's compare it with the room door width. Room door width is 3.5 units. Bathroom door width is 2.5 units. Since 2.5 < 3.5, the bathroom door is narrower.

Diagram 4

Answer

(i) The door is 8 units from the left wall (y-axis). The door is 0 units from the x-axis. (ii) The coordinates of D1\text{D}_1 are (8, 0). (iii) The width of the door is 3.5 units. This is a comfortable width for a room door. Yes, a person in a wheelchair will be able to enter easily. (iv) The bathroom door is narrower than the room door.

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