Triangles | Activity

Question 4

Draw two line segments BCBC and EFEF of two different lengths, say 3 cm3\text{ cm} and 5 cm5\text{ cm} respectively. Then, at the points BB and CC respectively, construct angles PBC\angle PBC and QCB\angle QCB of some measures, say, 6060^\circ and 4040^\circ. Also, at the points EE and FF, construct angles REF\angle REF and SFE\angle SFE of 6060^\circ and 4040^\circ respectively (see Fig. 6.23).

Question diagram 1
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Solution
Understand the Question
  • The sum of all interior angles in any triangle is always 180180^\circ.
  • When constructing triangles given two angles, the third angle is uniquely determined by the angle sum property.
  • AAA Similarity Criterion: If corresponding angles of two triangles are equal, the triangles are similar.
  • For two triangles to be congruent, their corresponding side lengths must also be equal.

Step 1 · Find A\angle A in ABC\triangle ABC

In ABC\triangle ABC, B=60\angle B = 60^\circ and C=40\angle C = 40^\circ.Diagram 1

By the angle sum property of a triangle

A+B+C=180A+60+40=180A+100=180A=180100=80\begin{aligned} \angle A + \angle B + \angle C &= 180^\circ \\ \angle A + 60^\circ + 40^\circ &= 180^\circ \\ \angle A + 100^\circ &= 180^\circ \\ \angle A &= 180^\circ - 100^\circ = 80^\circ \end{aligned}

Step 2 · Find D\angle D in DEF\triangle DEF

In DEF\triangle DEF, E=60\angle E = 60^\circ and F=40\angle F = 40^\circ.Diagram 2

By the angle sum property of a triangle

D+E+F=180D+60+40=180D+100=180D=180100=80\begin{aligned} \angle D + \angle E + \angle F &= 180^\circ \\ \angle D + 60^\circ + 40^\circ &= 180^\circ \\ \angle D + 100^\circ &= 180^\circ \\ \angle D &= 180^\circ - 100^\circ = 80^\circ \end{aligned}

Step 3 · Compare the Triangles

Comparing ABC\triangle ABC and DEF\triangle DEF:

  • Corresponding angles are equal: A=D=80\angle A = \angle D = 80^\circ, B=E=60\angle B = \angle E = 60^\circ, and C=F=40\angle C = \angle F = 40^\circ.
  • By the AAA similarity criterion, ABCDEF\triangle ABC \sim \triangle DEF.
  • Since corresponding sides have different lengths (BC=3 cmEF=5 cmBC = 3\text{ cm} \neq EF = 5\text{ cm}), the triangles are not congruent.
Answer

A=80\angle A = 80^\circ and D=80\angle D = 80^\circ. The triangles ABC\triangle ABC and DEF\triangle DEF are similar, but not congruent.

Common Mistakes
  • Confusing Similarity with Congruence: Having all three corresponding angles equal (AAA) guarantees similarity, not congruence. Equal side lengths are necessary for congruence.
  • Angle Sum Errors: Making arithmetic mistakes when calculating the third angle from 180(B+C)180^\circ - (\angle B + \angle C).
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